Solve x-1/3geq1/8

$$x - \frac { 1 } { 3 } \geq \frac { 1 } { 8 }$$

Solve for x

$$x\geq \frac{11}{24}$$

Solution Steps

Add \frac{1}{3} to both sides.

$$x\geq \frac{1}{8}+\frac{1}{3}$$

Least common multiple of 8 and 3 is 24. Convert \frac{1}{8} and \frac{1}{3} to fractions with denominator 24.

$$x\geq \frac{3}{24}+\frac{8}{24}$$

Since \frac{3}{24} and \frac{8}{24} have the same denominator, add them by adding their numerators.

$$x\geq \frac{3+8}{24}$$

Add 3 and 8 to get 11.

$$x\geq \frac{11}{24}$$