Solve x(t)=t^2-24t+13,t=18

$$x ( t ) = t ^ { 2 } - 24 t + 13 , t = 18$$

Solve for x, t

$$x = -\frac{95}{18} = -5\frac{5}{18} \approx -5.277777778$$

$$t=18$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$x\times 18=18^{2}-24\times 18+13$$

Calculate 18 to the power of 2 and get 324.

$$x\times 18=324-24\times 18+13$$

Multiply -24 and 18 to get -432.

$$x\times 18=324-432+13$$

Subtract 432 from 324 to get -108.

$$x\times 18=-108+13$$

Add -108 and 13 to get -95.

$$x\times 18=-95$$

Divide both sides by 18.

$$x=-\frac{95}{18}$$

The system is now solved.

$$x=-\frac{95}{18} t=18$$