Solve x(-2)^2-3(-2)-9

$$x ( - 2 ) ^ { 2 } - 3 ( - 2 ) - 9$$

Evaluate

$$4x-3$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$x\times 4-3\left(-2\right)-9$$

Multiply 3 and -2 to get -6.

$$x\times 4-\left(-6\right)-9$$

The opposite of -6 is 6.

$$x\times 4+6-9$$

Subtract 9 from 6 to get -3.

$$x\times 4-3$$

Differentiate w.r.t. x

$$4$$

Steps Using Derivative Rule for Sum

Calculate -2 to the power of 2 and get 4.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\times 4-3\left(-2\right)-9)$$

Multiply 3 and -2 to get -6.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\times 4-\left(-6\right)-9)$$

The opposite of -6 is 6.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\times 4+6-9)$$

Subtract 9 from 6 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\times 4-3)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$4x^{1-1}$$

Subtract 1 from 1.

$$4x^{0}$$

For any term t except 0, t^{0}=1.

$$4\times 1$$

For any term t, t\times 1=t and 1t=t.

$$4$$