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x\left(-\frac{5}{3}\right)\leq \frac{17}{14}+\frac{16}{21}
Add \frac{16}{21} to both sides.
x\left(-\frac{5}{3}\right)\leq \frac{51}{42}+\frac{32}{42}
Least common multiple of 14 and 21 is 42. Convert \frac{17}{14} and \frac{16}{21} to fractions with denominator 42.
x\left(-\frac{5}{3}\right)\leq \frac{51+32}{42}
Since \frac{51}{42} and \frac{32}{42} have the same denominator, add them by adding their numerators.
x\left(-\frac{5}{3}\right)\leq \frac{83}{42}
Add 51 and 32 to get 83.
x\geq \frac{83}{42}\left(-\frac{3}{5}\right)
Multiply both sides by -\frac{3}{5}, the reciprocal of -\frac{5}{3}. Since -\frac{5}{3} is negative, the inequality direction is changed.
x\geq \frac{83\left(-3\right)}{42\times 5}
Multiply \frac{83}{42} times -\frac{3}{5} by multiplying numerator times numerator and denominator times denominator.
x\geq \frac{-249}{210}
Do the multiplications in the fraction \frac{83\left(-3\right)}{42\times 5}.
x\geq -\frac{83}{70}
Reduce the fraction \frac{-249}{210} to lowest terms by extracting and canceling out 3.