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x^{2}+6=7
Multiply x and x to get x^{2}.
x^{2}=7-6
Subtract 6 from both sides.
x^{2}=1
Subtract 6 from 7 to get 1.
x=1 x=-1
Take the square root of both sides of the equation.
x^{2}+6=7
Multiply x and x to get x^{2}.
x^{2}+6-7=0
Subtract 7 from both sides.
x^{2}-1=0
Subtract 7 from 6 to get -1.
x=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-1\right)}}{2}
Square 0.
x=\frac{0±\sqrt{4}}{2}
Multiply -4 times -1.
x=\frac{0±2}{2}
Take the square root of 4.
x=1
Now solve the equation x=\frac{0±2}{2} when ± is plus. Divide 2 by 2.
x=-1
Now solve the equation x=\frac{0±2}{2} when ± is minus. Divide -2 by 2.
x=1 x=-1
The equation is now solved.