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x^{2}\times 2=400
Multiply x and x to get x^{2}.
x^{2}=\frac{400}{2}
Divide both sides by 2.
x^{2}=200
Divide 400 by 2 to get 200.
x=10\sqrt{2} x=-10\sqrt{2}
Take the square root of both sides of the equation.
x^{2}\times 2=400
Multiply x and x to get x^{2}.
x^{2}\times 2-400=0
Subtract 400 from both sides.
2x^{2}-400=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 2\left(-400\right)}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 0 for b, and -400 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 2\left(-400\right)}}{2\times 2}
Square 0.
x=\frac{0±\sqrt{-8\left(-400\right)}}{2\times 2}
Multiply -4 times 2.
x=\frac{0±\sqrt{3200}}{2\times 2}
Multiply -8 times -400.
x=\frac{0±40\sqrt{2}}{2\times 2}
Take the square root of 3200.
x=\frac{0±40\sqrt{2}}{4}
Multiply 2 times 2.
x=10\sqrt{2}
Now solve the equation x=\frac{0±40\sqrt{2}}{4} when ± is plus.
x=-10\sqrt{2}
Now solve the equation x=\frac{0±40\sqrt{2}}{4} when ± is minus.
x=10\sqrt{2} x=-10\sqrt{2}
The equation is now solved.