Solve for x
x=12\sqrt{35}\approx 70.992957397
x=-12\sqrt{35}\approx -70.992957397
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x^{2}\times 1.5=7560
Multiply x and x to get x^{2}.
x^{2}=\frac{7560}{1.5}
Divide both sides by 1.5.
x^{2}=\frac{75600}{15}
Expand \frac{7560}{1.5} by multiplying both numerator and the denominator by 10.
x^{2}=5040
Divide 75600 by 15 to get 5040.
x=12\sqrt{35} x=-12\sqrt{35}
Take the square root of both sides of the equation.
x^{2}\times 1.5=7560
Multiply x and x to get x^{2}.
x^{2}\times 1.5-7560=0
Subtract 7560 from both sides.
1.5x^{2}-7560=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 1.5\left(-7560\right)}}{2\times 1.5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1.5 for a, 0 for b, and -7560 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 1.5\left(-7560\right)}}{2\times 1.5}
Square 0.
x=\frac{0±\sqrt{-6\left(-7560\right)}}{2\times 1.5}
Multiply -4 times 1.5.
x=\frac{0±\sqrt{45360}}{2\times 1.5}
Multiply -6 times -7560.
x=\frac{0±36\sqrt{35}}{2\times 1.5}
Take the square root of 45360.
x=\frac{0±36\sqrt{35}}{3}
Multiply 2 times 1.5.
x=12\sqrt{35}
Now solve the equation x=\frac{0±36\sqrt{35}}{3} when ± is plus.
x=-12\sqrt{35}
Now solve the equation x=\frac{0±36\sqrt{35}}{3} when ± is minus.
x=12\sqrt{35} x=-12\sqrt{35}
The equation is now solved.
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