Solve x*28x=0.8x^2

$$x \cdot 28 x = 0.8 x ^ { 2 }$$

Solve for x

$$x=0$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$x^{2}\times 28=0.8x^{2}$$

Subtract 0.8x^{2} from both sides.

$$x^{2}\times 28-0.8x^{2}=0$$

Combine x^{2}\times 28 and -0.8x^{2} to get 27.2x^{2}.

$$27.2x^{2}=0$$

Divide both sides by 27.2. Zero divided by any non-zero number gives zero.

$$x^{2}=0$$

Take the square root of both sides of the equation.

$$x=0 x=0$$

The equation is now solved. Solutions are the same.

$$x=0$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$x^{2}\times 28=0.8x^{2}$$

Subtract 0.8x^{2} from both sides.

$$x^{2}\times 28-0.8x^{2}=0$$

Combine x^{2}\times 28 and -0.8x^{2} to get 27.2x^{2}.

$$27.2x^{2}=0$$

Divide both sides by 27.2. Zero divided by any non-zero number gives zero.

$$x^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$x=\frac{0±0}{2}$$

Divide 0 by 2.

$$x=0$$