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x\times \frac{2}{3}-\frac{7}{8}=\frac{10}{8}-\frac{1}{8}
Least common multiple of 4 and 8 is 8. Convert \frac{5}{4} and \frac{1}{8} to fractions with denominator 8.
x\times \frac{2}{3}-\frac{7}{8}=\frac{10-1}{8}
Since \frac{10}{8} and \frac{1}{8} have the same denominator, subtract them by subtracting their numerators.
x\times \frac{2}{3}-\frac{7}{8}=\frac{9}{8}
Subtract 1 from 10 to get 9.
x\times \frac{2}{3}=\frac{9}{8}+\frac{7}{8}
Add \frac{7}{8} to both sides.
x\times \frac{2}{3}=\frac{9+7}{8}
Since \frac{9}{8} and \frac{7}{8} have the same denominator, add them by adding their numerators.
x\times \frac{2}{3}=\frac{16}{8}
Add 9 and 7 to get 16.
x\times \frac{2}{3}=2
Divide 16 by 8 to get 2.
x=2\times \frac{3}{2}
Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.
x=3
Cancel out 2 and 2.