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x^{5}\left(x^{2}-17x-18\right)
Factor out x^{5}.
a+b=-17 ab=1\left(-18\right)=-18
Consider x^{2}-17x-18. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx-18. To find a and b, set up a system to be solved.
1,-18 2,-9 3,-6
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -18.
1-18=-17 2-9=-7 3-6=-3
Calculate the sum for each pair.
a=-18 b=1
The solution is the pair that gives sum -17.
\left(x^{2}-18x\right)+\left(x-18\right)
Rewrite x^{2}-17x-18 as \left(x^{2}-18x\right)+\left(x-18\right).
x\left(x-18\right)+x-18
Factor out x in x^{2}-18x.
\left(x-18\right)\left(x+1\right)
Factor out common term x-18 by using distributive property.
x^{5}\left(x-18\right)\left(x+1\right)
Rewrite the complete factored expression.