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Solve for x (complex solution)
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t^{2}-4t-46=0
Substitute t for x^{2}.
t=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 1\left(-46\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -4 for b, and -46 for c in the quadratic formula.
t=\frac{4±10\sqrt{2}}{2}
Do the calculations.
t=5\sqrt{2}+2 t=2-5\sqrt{2}
Solve the equation t=\frac{4±10\sqrt{2}}{2} when ± is plus and when ± is minus.
x=-\sqrt{5\sqrt{2}+2} x=\sqrt{5\sqrt{2}+2} x=-i\sqrt{-\left(2-5\sqrt{2}\right)} x=i\sqrt{-\left(2-5\sqrt{2}\right)}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.
t^{2}-4t-46=0
Substitute t for x^{2}.
t=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 1\left(-46\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -4 for b, and -46 for c in the quadratic formula.
t=\frac{4±10\sqrt{2}}{2}
Do the calculations.
t=5\sqrt{2}+2 t=2-5\sqrt{2}
Solve the equation t=\frac{4±10\sqrt{2}}{2} when ± is plus and when ± is minus.
x=\sqrt{5\sqrt{2}+2} x=-\sqrt{5\sqrt{2}+2}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for positive t.