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t^{2}-13t+30=0
Substitute t for x^{2}.
t=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}-4\times 1\times 30}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -13 for b, and 30 for c in the quadratic formula.
t=\frac{13±7}{2}
Do the calculations.
t=10 t=3
Solve the equation t=\frac{13±7}{2} when ± is plus and when ± is minus.
x=\sqrt{10} x=-\sqrt{10} x=\sqrt{3} x=-\sqrt{3}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.