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t^{2}-10t+24=0
Substitute t for x^{2}.
t=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}-4\times 1\times 24}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -10 for b, and 24 for c in the quadratic formula.
t=\frac{10±2}{2}
Do the calculations.
t=6 t=4
Solve the equation t=\frac{10±2}{2} when ± is plus and when ± is minus.
x=\sqrt{6} x=-\sqrt{6} x=2 x=-2
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.