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3x^{4}-2x^{3}-31x^{2}+8x+6=0
Multiply both sides of the equation by 3.
±2,±6,±1,±3,±\frac{2}{3},±\frac{1}{3}
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 6 and q divides the leading coefficient 3. List all candidates \frac{p}{q}.
x=-3
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
3x^{3}-11x^{2}+2x+2=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 3x^{4}-2x^{3}-31x^{2}+8x+6 by x+3 to get 3x^{3}-11x^{2}+2x+2. Solve the equation where the result equals to 0.
±\frac{2}{3},±2,±\frac{1}{3},±1
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 2 and q divides the leading coefficient 3. List all candidates \frac{p}{q}.
x=-\frac{1}{3}
Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.
x^{2}-4x+2=0
By Factor theorem, x-k is a factor of the polynomial for each root k. Divide 3x^{3}-11x^{2}+2x+2 by 3\left(x+\frac{1}{3}\right)=3x+1 to get x^{2}-4x+2. Solve the equation where the result equals to 0.
x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 1\times 2}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -4 for b, and 2 for c in the quadratic formula.
x=\frac{4±2\sqrt{2}}{2}
Do the calculations.
x=2-\sqrt{2} x=\sqrt{2}+2
Solve the equation x^{2}-4x+2=0 when ± is plus and when ± is minus.
x=-3 x=-\frac{1}{3} x=2-\sqrt{2} x=\sqrt{2}+2
List all found solutions.