Solve x^3-3x+7divx^2+3

$$x ^ { 3 } - 3 x + 7 \div x ^ { 2 } + 3$$

Evaluate

$$x^{3}-3x+3+\frac{7}{x^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{3}-3x+3 times \frac{x^{2}}{x^{2}}.

$$\frac{\left(x^{3}-3x+3\right)x^{2}}{x^{2}}+\frac{7}{x^{2}}$$

Since \frac{\left(x^{3}-3x+3\right)x^{2}}{x^{2}} and \frac{7}{x^{2}} have the same denominator, add them by adding their numerators.

$$\frac{\left(x^{3}-3x+3\right)x^{2}+7}{x^{2}}$$

Do the multiplications in \left(x^{3}-3x+3\right)x^{2}+7.

$$\frac{x^{5}-3x^{3}+3x^{2}+7}{x^{2}}$$

Factor

$$\frac{x^{5}-3x^{3}+3x^{2}+7}{x^{2}}$$