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\left(x-9\right)\left(x^{2}-6x+9\right)
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -81 and q divides the leading coefficient 1. One such root is 9. Factor the polynomial by dividing it by x-9.
\left(x-3\right)^{2}
Consider x^{2}-6x+9. Use the perfect square formula, a^{2}-2ab+b^{2}=\left(a-b\right)^{2}, where a=x and b=3.
\left(x-9\right)\left(x-3\right)^{2}
Rewrite the complete factored expression.