Solve x^3(-5/4x^2y)(28/5x^3y^4)

$$x ^ { 3 } ( - \frac { 5 } { 4 } x ^ { 2 } y ) ( \frac { 28 } { 5 } x ^ { 3 } y ^ { 4 } )$$

Evaluate

$$-7y^{5}x^{8}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 3 and 2 to get 5.

$$x^{5}\left(-\frac{5}{4}\right)y\times \frac{28}{5}x^{3}y^{4}$$

To multiply powers of the same base, add their exponents. Add 5 and 3 to get 8.

$$x^{8}\left(-\frac{5}{4}\right)y\times \frac{28}{5}y^{4}$$

To multiply powers of the same base, add their exponents. Add 1 and 4 to get 5.

$$x^{8}\left(-\frac{5}{4}\right)y^{5}\times \frac{28}{5}$$

Multiply -\frac{5}{4} and \frac{28}{5} to get -7.

$$x^{8}\left(-7\right)y^{5}$$

Differentiate w.r.t. x

$$-56y^{5}x^{7}$$