Solve x^2y+x^2=25

$$x ^ { 2 } y + x ^ { 2 } = 25$$

Solve for y

$$y=-1+\frac{25}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$x^{2}y=25-x^{2}$$

Divide both sides by x^{2}.

$$\frac{x^{2}y}{x^{2}}=\frac{25-x^{2}}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$y=\frac{25-x^{2}}{x^{2}}$$

Divide -x^{2}+25 by x^{2}.

$$y=-1+\frac{25}{x^{2}}$$

Solve for x (complex solution)

$$x=-5\left(y+1\right)^{-\frac{1}{2}}$$

$$x=5\left(y+1\right)^{-\frac{1}{2}}\text{, }y\neq -1$$

Solve for x

$$x=\frac{5}{\sqrt{y+1}}$$

$$x=-\frac{5}{\sqrt{y+1}}\text{, }y>-1$$