Solve x^2-y-12=1

$$x ^ { 2 } - y - 12 = 1$$

Solve for y

$$y=x^{2}-13$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$-y-12=1-x^{2}$$

Add 12 to both sides.

$$-y=1-x^{2}+12$$

Add 1 and 12 to get 13.

$$-y=13-x^{2}$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{13-x^{2}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{13-x^{2}}{-1}$$

Divide 13-x^{2} by -1.

$$y=x^{2}-13$$

Solve for x (complex solution)

$$x=-\sqrt{y+13}$$

$$x=\sqrt{y+13}$$

Solve for x

$$x=\sqrt{y+13}$$

$$x=-\sqrt{y+13}\text{, }y\geq -13$$