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\left(x-y^{4}\right)\left(x+y^{4}\right)
Rewrite x^{2}-y^{8} as x^{2}-\left(y^{4}\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).