Solve x^2-8y+5=9

$$x ^ { 2 } - 8 y + 5 = 9$$

Solve for y

$$y=\frac{x^{2}-4}{8}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$-8y+5=9-x^{2}$$

Subtract 5 from both sides.

$$-8y=9-x^{2}-5$$

Subtract 5 from 9 to get 4.

$$-8y=4-x^{2}$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{4-x^{2}}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{4-x^{2}}{-8}$$

Divide -x^{2}+4 by -8.

$$y=\frac{x^{2}}{8}-\frac{1}{2}$$

Solve for x (complex solution)

$$x=-2\sqrt{2y+1}$$

$$x=2\sqrt{2y+1}$$

Solve for x

$$x=2\sqrt{2y+1}$$

$$x=-2\sqrt{2y+1}\text{, }y\geq -\frac{1}{2}$$