Solve x^2-8t-12=0

$$x ^ { 2 } - 8 t - 12 = 0$$

Solve for t

$$t=\frac{x^{2}-12}{8}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-8t-12=-x^{2}$$

Add 12 to both sides.

$$-8t=-x^{2}+12$$

The equation is in standard form.

$$-8t=12-x^{2}$$

Divide both sides by -8.

$$\frac{-8t}{-8}=\frac{12-x^{2}}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$t=\frac{12-x^{2}}{-8}$$

Divide -x^{2}+12 by -8.

$$t=\frac{x^{2}}{8}-\frac{3}{2}$$

Solve for x (complex solution)

$$x=-2\sqrt{2t+3}$$

$$x=2\sqrt{2t+3}$$

Solve for x

$$x=2\sqrt{2t+3}$$

$$x=-2\sqrt{2t+3}\text{, }t\geq -\frac{3}{2}$$