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x^{2}-54x-264=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-54\right)±\sqrt{\left(-54\right)^{2}-4\left(-264\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -54 for b, and -264 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-54\right)±\sqrt{2916-4\left(-264\right)}}{2}
Square -54.
x=\frac{-\left(-54\right)±\sqrt{2916+1056}}{2}
Multiply -4 times -264.
x=\frac{-\left(-54\right)±\sqrt{3972}}{2}
Add 2916 to 1056.
x=\frac{-\left(-54\right)±2\sqrt{993}}{2}
Take the square root of 3972.
x=\frac{54±2\sqrt{993}}{2}
The opposite of -54 is 54.
x=\frac{2\sqrt{993}+54}{2}
Now solve the equation x=\frac{54±2\sqrt{993}}{2} when ± is plus. Add 54 to 2\sqrt{993}.
x=\sqrt{993}+27
Divide 54+2\sqrt{993} by 2.
x=\frac{54-2\sqrt{993}}{2}
Now solve the equation x=\frac{54±2\sqrt{993}}{2} when ± is minus. Subtract 2\sqrt{993} from 54.
x=27-\sqrt{993}
Divide 54-2\sqrt{993} by 2.
x=\sqrt{993}+27 x=27-\sqrt{993}
The equation is now solved.
x^{2}-54x-264=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-54x-264-\left(-264\right)=-\left(-264\right)
Add 264 to both sides of the equation.
x^{2}-54x=-\left(-264\right)
Subtracting -264 from itself leaves 0.
x^{2}-54x=264
Subtract -264 from 0.
x^{2}-54x+\left(-27\right)^{2}=264+\left(-27\right)^{2}
Divide -54, the coefficient of the x term, by 2 to get -27. Then add the square of -27 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-54x+729=264+729
Square -27.
x^{2}-54x+729=993
Add 264 to 729.
\left(x-27\right)^{2}=993
Factor x^{2}-54x+729. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-27\right)^{2}}=\sqrt{993}
Take the square root of both sides of the equation.
x-27=\sqrt{993} x-27=-\sqrt{993}
Simplify.
x=\sqrt{993}+27 x=27-\sqrt{993}
Add 27 to both sides of the equation.
x ^ 2 -54x -264 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 54 rs = -264
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 27 - u s = 27 + u
Two numbers r and s sum up to 54 exactly when the average of the two numbers is \frac{1}{2}*54 = 27. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(27 - u) (27 + u) = -264
To solve for unknown quantity u, substitute these in the product equation rs = -264
729 - u^2 = -264
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -264-729 = -993
Simplify the expression by subtracting 729 on both sides
u^2 = 993 u = \pm\sqrt{993} = \pm \sqrt{993}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =27 - \sqrt{993} = -4.512 s = 27 + \sqrt{993} = 58.512
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.