Solve x^2-5x+4=(x-1)(x-1)

$$x ^ { 2 } - 5 x + 4 = ( x - 1 ) ( x - 1 )$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Multiply x-1 and x-1 to get \left(x-1\right)^{2}.

$$x^{2}-5x+4=\left(x-1\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.

$$x^{2}-5x+4=x^{2}-2x+1$$

Subtract x^{2} from both sides.

$$x^{2}-5x+4-x^{2}=-2x+1$$

Combine x^{2} and -x^{2} to get 0.

$$-5x+4=-2x+1$$

Add 2x to both sides.

$$-5x+4+2x=1$$

Combine -5x and 2x to get -3x.

$$-3x+4=1$$

Subtract 4 from both sides.

$$-3x=1-4$$

Subtract 4 from 1 to get -3.

$$-3x=-3$$

Divide both sides by -3.

$$x=\frac{-3}{-3}$$

Divide -3 by -3 to get 1.

$$x=1$$