Solve x^2-4y=1

$$x ^ { 2 } - 4 y = 1$$

Solve for y

$$y=\frac{x^{2}-1}{4}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$-4y=1-x^{2}$$

Divide both sides by -4.

$$\frac{-4y}{-4}=\frac{1-x^{2}}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$y=\frac{1-x^{2}}{-4}$$

Divide -x^{2}+1 by -4.

$$y=\frac{x^{2}-1}{4}$$

Solve for x (complex solution)

$$x=-\sqrt{4y+1}$$

$$x=\sqrt{4y+1}$$

Solve for x

$$x=\sqrt{4y+1}$$

$$x=-\sqrt{4y+1}\text{, }y\geq -\frac{1}{4}$$