Skip to main content
Solve for x (complex solution)
Tick mark Image
Graph

Similar Problems from Web Search

Share

x^{2}-30x+1000=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-30\right)±\sqrt{\left(-30\right)^{2}-4\times 1000}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -30 for b, and 1000 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-30\right)±\sqrt{900-4\times 1000}}{2}
Square -30.
x=\frac{-\left(-30\right)±\sqrt{900-4000}}{2}
Multiply -4 times 1000.
x=\frac{-\left(-30\right)±\sqrt{-3100}}{2}
Add 900 to -4000.
x=\frac{-\left(-30\right)±10\sqrt{31}i}{2}
Take the square root of -3100.
x=\frac{30±10\sqrt{31}i}{2}
The opposite of -30 is 30.
x=\frac{30+10\sqrt{31}i}{2}
Now solve the equation x=\frac{30±10\sqrt{31}i}{2} when ± is plus. Add 30 to 10i\sqrt{31}.
x=15+5\sqrt{31}i
Divide 30+10i\sqrt{31} by 2.
x=\frac{-10\sqrt{31}i+30}{2}
Now solve the equation x=\frac{30±10\sqrt{31}i}{2} when ± is minus. Subtract 10i\sqrt{31} from 30.
x=-5\sqrt{31}i+15
Divide 30-10i\sqrt{31} by 2.
x=15+5\sqrt{31}i x=-5\sqrt{31}i+15
The equation is now solved.
x^{2}-30x+1000=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-30x+1000-1000=-1000
Subtract 1000 from both sides of the equation.
x^{2}-30x=-1000
Subtracting 1000 from itself leaves 0.
x^{2}-30x+\left(-15\right)^{2}=-1000+\left(-15\right)^{2}
Divide -30, the coefficient of the x term, by 2 to get -15. Then add the square of -15 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-30x+225=-1000+225
Square -15.
x^{2}-30x+225=-775
Add -1000 to 225.
\left(x-15\right)^{2}=-775
Factor x^{2}-30x+225. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-15\right)^{2}}=\sqrt{-775}
Take the square root of both sides of the equation.
x-15=5\sqrt{31}i x-15=-5\sqrt{31}i
Simplify.
x=15+5\sqrt{31}i x=-5\sqrt{31}i+15
Add 15 to both sides of the equation.
x ^ 2 -30x +1000 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 30 rs = 1000
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 15 - u s = 15 + u
Two numbers r and s sum up to 30 exactly when the average of the two numbers is \frac{1}{2}*30 = 15. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(15 - u) (15 + u) = 1000
To solve for unknown quantity u, substitute these in the product equation rs = 1000
225 - u^2 = 1000
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 1000-225 = 775
Simplify the expression by subtracting 225 on both sides
u^2 = -775 u = \pm\sqrt{-775} = \pm \sqrt{775}i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =15 - \sqrt{775}i s = 15 + \sqrt{775}i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.