Solve for x
x=8\sqrt{10}+12\approx 37.298221281
x=12-8\sqrt{10}\approx -13.298221281
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x^{2}-24x=496
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x^{2}-24x-496=496-496
Subtract 496 from both sides of the equation.
x^{2}-24x-496=0
Subtracting 496 from itself leaves 0.
x=\frac{-\left(-24\right)±\sqrt{\left(-24\right)^{2}-4\left(-496\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -24 for b, and -496 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-24\right)±\sqrt{576-4\left(-496\right)}}{2}
Square -24.
x=\frac{-\left(-24\right)±\sqrt{576+1984}}{2}
Multiply -4 times -496.
x=\frac{-\left(-24\right)±\sqrt{2560}}{2}
Add 576 to 1984.
x=\frac{-\left(-24\right)±16\sqrt{10}}{2}
Take the square root of 2560.
x=\frac{24±16\sqrt{10}}{2}
The opposite of -24 is 24.
x=\frac{16\sqrt{10}+24}{2}
Now solve the equation x=\frac{24±16\sqrt{10}}{2} when ± is plus. Add 24 to 16\sqrt{10}.
x=8\sqrt{10}+12
Divide 24+16\sqrt{10} by 2.
x=\frac{24-16\sqrt{10}}{2}
Now solve the equation x=\frac{24±16\sqrt{10}}{2} when ± is minus. Subtract 16\sqrt{10} from 24.
x=12-8\sqrt{10}
Divide 24-16\sqrt{10} by 2.
x=8\sqrt{10}+12 x=12-8\sqrt{10}
The equation is now solved.
x^{2}-24x=496
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-24x+\left(-12\right)^{2}=496+\left(-12\right)^{2}
Divide -24, the coefficient of the x term, by 2 to get -12. Then add the square of -12 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-24x+144=496+144
Square -12.
x^{2}-24x+144=640
Add 496 to 144.
\left(x-12\right)^{2}=640
Factor x^{2}-24x+144. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-12\right)^{2}}=\sqrt{640}
Take the square root of both sides of the equation.
x-12=8\sqrt{10} x-12=-8\sqrt{10}
Simplify.
x=8\sqrt{10}+12 x=12-8\sqrt{10}
Add 12 to both sides of the equation.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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Linear equation
y = 3x + 4
Arithmetic
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Matrix
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}