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x^{2}-226x+1103=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-226\right)±\sqrt{\left(-226\right)^{2}-4\times 1103}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -226 for b, and 1103 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-226\right)±\sqrt{51076-4\times 1103}}{2}
Square -226.
x=\frac{-\left(-226\right)±\sqrt{51076-4412}}{2}
Multiply -4 times 1103.
x=\frac{-\left(-226\right)±\sqrt{46664}}{2}
Add 51076 to -4412.
x=\frac{-\left(-226\right)±2\sqrt{11666}}{2}
Take the square root of 46664.
x=\frac{226±2\sqrt{11666}}{2}
The opposite of -226 is 226.
x=\frac{2\sqrt{11666}+226}{2}
Now solve the equation x=\frac{226±2\sqrt{11666}}{2} when ± is plus. Add 226 to 2\sqrt{11666}.
x=\sqrt{11666}+113
Divide 226+2\sqrt{11666} by 2.
x=\frac{226-2\sqrt{11666}}{2}
Now solve the equation x=\frac{226±2\sqrt{11666}}{2} when ± is minus. Subtract 2\sqrt{11666} from 226.
x=113-\sqrt{11666}
Divide 226-2\sqrt{11666} by 2.
x=\sqrt{11666}+113 x=113-\sqrt{11666}
The equation is now solved.
x^{2}-226x+1103=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-226x+1103-1103=-1103
Subtract 1103 from both sides of the equation.
x^{2}-226x=-1103
Subtracting 1103 from itself leaves 0.
x^{2}-226x+\left(-113\right)^{2}=-1103+\left(-113\right)^{2}
Divide -226, the coefficient of the x term, by 2 to get -113. Then add the square of -113 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-226x+12769=-1103+12769
Square -113.
x^{2}-226x+12769=11666
Add -1103 to 12769.
\left(x-113\right)^{2}=11666
Factor x^{2}-226x+12769. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-113\right)^{2}}=\sqrt{11666}
Take the square root of both sides of the equation.
x-113=\sqrt{11666} x-113=-\sqrt{11666}
Simplify.
x=\sqrt{11666}+113 x=113-\sqrt{11666}
Add 113 to both sides of the equation.
x ^ 2 -226x +1103 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 226 rs = 1103
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 113 - u s = 113 + u
Two numbers r and s sum up to 226 exactly when the average of the two numbers is \frac{1}{2}*226 = 113. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(113 - u) (113 + u) = 1103
To solve for unknown quantity u, substitute these in the product equation rs = 1103
12769 - u^2 = 1103
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 1103-12769 = -11666
Simplify the expression by subtracting 12769 on both sides
u^2 = 11666 u = \pm\sqrt{11666} = \pm \sqrt{11666}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =113 - \sqrt{11666} = 4.991 s = 113 + \sqrt{11666} = 221.009
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.