Solve x^2-2x+8y+9=0

$$x ^ { 2 } - 2 x + 8 y + 9 = 0$$

Solve for y

$$y=-\frac{x^{2}}{8}+\frac{x}{4}-\frac{9}{8}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2x+8y+9=-x^{2}$$

Add 2x to both sides.

$$8y+9=-x^{2}+2x$$

Subtract 9 from both sides.

$$8y=-x^{2}+2x-9$$

Divide both sides by 8.

$$\frac{8y}{8}=\frac{-x^{2}+2x-9}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$y=\frac{-x^{2}+2x-9}{8}$$

Divide -x^{2}+2x-9 by 8.

$$y=-\frac{x^{2}}{8}+\frac{x}{4}-\frac{9}{8}$$

Solve for x (complex solution)

$$x=2\sqrt{-2y-2}+1$$

$$x=-2\sqrt{-2y-2}+1$$

Solve for x

$$x=2\sqrt{-2y-2}+1$$

$$x=-2\sqrt{-2y-2}+1\text{, }y\leq -1$$