Solve x^2-2p-2=0

$$x ^ { 2 } - 2 p - 2 = 0$$

Solve for p

$$p=\frac{x^{2}-2}{2}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-2p-2=-x^{2}$$

Add 2 to both sides.

$$-2p=-x^{2}+2$$

The equation is in standard form.

$$-2p=2-x^{2}$$

Divide both sides by -2.

$$\frac{-2p}{-2}=\frac{2-x^{2}}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$p=\frac{2-x^{2}}{-2}$$

Divide -x^{2}+2 by -2.

$$p=\frac{x^{2}}{2}-1$$

Solve for x (complex solution)

$$x=-\sqrt{2\left(p+1\right)}$$

$$x=\sqrt{2\left(p+1\right)}$$

Solve for x

$$x=\sqrt{2\left(p+1\right)}$$

$$x=-\sqrt{2\left(p+1\right)}\text{, }p\geq -1$$