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x^{2}=192
Add 192 to both sides. Anything plus zero gives itself.
x=8\sqrt{3} x=-8\sqrt{3}
Take the square root of both sides of the equation.
x^{2}-192=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-192\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -192 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-192\right)}}{2}
Square 0.
x=\frac{0±\sqrt{768}}{2}
Multiply -4 times -192.
x=\frac{0±16\sqrt{3}}{2}
Take the square root of 768.
x=8\sqrt{3}
Now solve the equation x=\frac{0±16\sqrt{3}}{2} when ± is plus.
x=-8\sqrt{3}
Now solve the equation x=\frac{0±16\sqrt{3}}{2} when ± is minus.
x=8\sqrt{3} x=-8\sqrt{3}
The equation is now solved.