Solve for x
x\in (-\infty,-3\sqrt{2}]\cup [3\sqrt{2},\infty)
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x^{2}\geq 18
Add 18 to both sides.
x^{2}\geq \left(3\sqrt{2}\right)^{2}
Calculate the square root of 18 and get 3\sqrt{2}. Rewrite 18 as \left(3\sqrt{2}\right)^{2}.
|x|\geq 3\sqrt{2}
Inequality holds for |x|\geq 3\sqrt{2}.
x\leq -3\sqrt{2}\text{; }x\geq 3\sqrt{2}
Rewrite |x|\geq 3\sqrt{2} as x\leq -3\sqrt{2}\text{; }x\geq 3\sqrt{2}.
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