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x^{2}-16x+64=32
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x^{2}-16x+64-32=32-32
Subtract 32 from both sides of the equation.
x^{2}-16x+64-32=0
Subtracting 32 from itself leaves 0.
x^{2}-16x+32=0
Subtract 32 from 64.
x=\frac{-\left(-16\right)±\sqrt{\left(-16\right)^{2}-4\times 32}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -16 for b, and 32 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-16\right)±\sqrt{256-4\times 32}}{2}
Square -16.
x=\frac{-\left(-16\right)±\sqrt{256-128}}{2}
Multiply -4 times 32.
x=\frac{-\left(-16\right)±\sqrt{128}}{2}
Add 256 to -128.
x=\frac{-\left(-16\right)±8\sqrt{2}}{2}
Take the square root of 128.
x=\frac{16±8\sqrt{2}}{2}
The opposite of -16 is 16.
x=\frac{8\sqrt{2}+16}{2}
Now solve the equation x=\frac{16±8\sqrt{2}}{2} when ± is plus. Add 16 to 8\sqrt{2}.
x=4\sqrt{2}+8
Divide 16+8\sqrt{2} by 2.
x=\frac{16-8\sqrt{2}}{2}
Now solve the equation x=\frac{16±8\sqrt{2}}{2} when ± is minus. Subtract 8\sqrt{2} from 16.
x=8-4\sqrt{2}
Divide 16-8\sqrt{2} by 2.
x=4\sqrt{2}+8 x=8-4\sqrt{2}
The equation is now solved.
x^{2}-16x+64=32
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\left(x-8\right)^{2}=32
Factor x^{2}-16x+64. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-8\right)^{2}}=\sqrt{32}
Take the square root of both sides of the equation.
x-8=4\sqrt{2} x-8=-4\sqrt{2}
Simplify.
x=4\sqrt{2}+8 x=8-4\sqrt{2}
Add 8 to both sides of the equation.