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\frac{2x^{2}-5x+2}{2}
Factor out \frac{1}{2}.
a+b=-5 ab=2\times 2=4
Consider 2x^{2}-5x+2. Factor the expression by grouping. First, the expression needs to be rewritten as 2x^{2}+ax+bx+2. To find a and b, set up a system to be solved.
-1,-4 -2,-2
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 4.
-1-4=-5 -2-2=-4
Calculate the sum for each pair.
a=-4 b=-1
The solution is the pair that gives sum -5.
\left(2x^{2}-4x\right)+\left(-x+2\right)
Rewrite 2x^{2}-5x+2 as \left(2x^{2}-4x\right)+\left(-x+2\right).
2x\left(x-2\right)-\left(x-2\right)
Factor out 2x in the first and -1 in the second group.
\left(x-2\right)\left(2x-1\right)
Factor out common term x-2 by using distributive property.
\frac{\left(x-2\right)\left(2x-1\right)}{2}
Rewrite the complete factored expression.