Factor
\frac{\left(7x-5\right)\left(7x+5\right)}{49}
Evaluate
x^{2}-\frac{25}{49}
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\frac{49x^{2}-25}{49}
Factor out \frac{1}{49}.
\left(7x-5\right)\left(7x+5\right)
Consider 49x^{2}-25. Rewrite 49x^{2}-25 as \left(7x\right)^{2}-5^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(7x-5\right)\left(7x+5\right)}{49}
Rewrite the complete factored expression.
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