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\frac{9x^{2}-16}{9}
Factor out \frac{1}{9}.
\left(3x-4\right)\left(3x+4\right)
Consider 9x^{2}-16. Rewrite 9x^{2}-16 as \left(3x\right)^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(3x-4\right)\left(3x+4\right)}{9}
Rewrite the complete factored expression.