Solve x^2-[x*(1-x/x+1)]

$$x ^ { 2 } - [ x \cdot ( 1 - \frac { x } { x + 1 } ) ]$$

Evaluate

$$\frac{x\left(x^{2}+x-1\right)}{x+1}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x+1}{x+1}.

$$x^{2}-x\left(\frac{x+1}{x+1}-\frac{x}{x+1}\right)$$

Since \frac{x+1}{x+1} and \frac{x}{x+1} have the same denominator, subtract them by subtracting their numerators.

$$x^{2}-x\times \frac{x+1-x}{x+1}$$

Combine like terms in x+1-x.

$$x^{2}-x\times \frac{1}{x+1}$$

Express x\times \frac{1}{x+1} as a single fraction.

$$x^{2}-\frac{x}{x+1}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{2} times \frac{x+1}{x+1}.

$$\frac{x^{2}\left(x+1\right)}{x+1}-\frac{x}{x+1}$$

Since \frac{x^{2}\left(x+1\right)}{x+1} and \frac{x}{x+1} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x^{2}\left(x+1\right)-x}{x+1}$$

Do the multiplications in x^{2}\left(x+1\right)-x.

$$\frac{x^{3}+x^{2}-x}{x+1}$$

Expand

$$\frac{x^{3}+x^{2}-x}{x+1}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x+1}{x+1}.

$$x^{2}-x\left(\frac{x+1}{x+1}-\frac{x}{x+1}\right)$$

Since \frac{x+1}{x+1} and \frac{x}{x+1} have the same denominator, subtract them by subtracting their numerators.

$$x^{2}-x\times \frac{x+1-x}{x+1}$$

Combine like terms in x+1-x.

$$x^{2}-x\times \frac{1}{x+1}$$

Express x\times \frac{1}{x+1} as a single fraction.

$$x^{2}-\frac{x}{x+1}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{2} times \frac{x+1}{x+1}.

$$\frac{x^{2}\left(x+1\right)}{x+1}-\frac{x}{x+1}$$

Since \frac{x^{2}\left(x+1\right)}{x+1} and \frac{x}{x+1} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x^{2}\left(x+1\right)-x}{x+1}$$

Do the multiplications in x^{2}\left(x+1\right)-x.

$$\frac{x^{3}+x^{2}-x}{x+1}$$