Solve for x
x\in (-\infty,-3\sqrt{7}]\cup [3\sqrt{7},\infty)
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x^{2}\geq \left(3\sqrt{7}\right)^{2}
Calculate the square root of 63 and get 3\sqrt{7}. Rewrite 63 as \left(3\sqrt{7}\right)^{2}.
|x|\geq 3\sqrt{7}
Inequality holds for |x|\geq 3\sqrt{7}.
x\leq -3\sqrt{7}\text{; }x\geq 3\sqrt{7}
Rewrite |x|\geq 3\sqrt{7} as x\leq -3\sqrt{7}\text{; }x\geq 3\sqrt{7}.
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