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x^{2}-x\times 50=0
Subtract x\times 50 from both sides.
x^{2}-50x=0
Multiply -1 and 50 to get -50.
x\left(x-50\right)=0
Factor out x.
x=0 x=50
To find equation solutions, solve x=0 and x-50=0.
x^{2}-x\times 50=0
Subtract x\times 50 from both sides.
x^{2}-50x=0
Multiply -1 and 50 to get -50.
x=\frac{-\left(-50\right)±\sqrt{\left(-50\right)^{2}}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -50 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-50\right)±50}{2}
Take the square root of \left(-50\right)^{2}.
x=\frac{50±50}{2}
The opposite of -50 is 50.
x=\frac{100}{2}
Now solve the equation x=\frac{50±50}{2} when ± is plus. Add 50 to 50.
x=50
Divide 100 by 2.
x=\frac{0}{2}
Now solve the equation x=\frac{50±50}{2} when ± is minus. Subtract 50 from 50.
x=0
Divide 0 by 2.
x=50 x=0
The equation is now solved.
x^{2}-x\times 50=0
Subtract x\times 50 from both sides.
x^{2}-50x=0
Multiply -1 and 50 to get -50.
x^{2}-50x+\left(-25\right)^{2}=\left(-25\right)^{2}
Divide -50, the coefficient of the x term, by 2 to get -25. Then add the square of -25 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-50x+625=625
Square -25.
\left(x-25\right)^{2}=625
Factor x^{2}-50x+625. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-25\right)^{2}}=\sqrt{625}
Take the square root of both sides of the equation.
x-25=25 x-25=-25
Simplify.
x=50 x=0
Add 25 to both sides of the equation.