Solve x^2=4982

$$x ^ { 2 } = 4982$$

Solve for x

$$x=\sqrt{4982}\approx 70.58328414$$

$$x=-\sqrt{4982}\approx -70.58328414$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x=\sqrt{4982} x=-\sqrt{4982}$$

Steps Using the Quadratic Formula

Subtract 4982 from both sides.

$$x^{2}-4982=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -4982 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-4982\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-4982\right)}}{2}$$

Multiply -4 times -4982.

$$x=\frac{0±\sqrt{19928}}{2}$$

Take the square root of 19928.

$$x=\frac{0±2\sqrt{4982}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{4982}}{2} when ± is plus.

$$x=\sqrt{4982}$$

Now solve the equation x=\frac{0±2\sqrt{4982}}{2} when ± is minus.

$$x=-\sqrt{4982}$$

The equation is now solved.

$$x=\sqrt{4982} x=-\sqrt{4982}$$