Solve x^2=4x4+4*1/4-3

$$x ^ { 2 } = 4 x 4 + 4 \times \frac { 1 } { 4 } - 3$$

Solve for x_4

$$x_{4}=\frac{x^{2}+2}{4}$$

Steps for Solving Linear Equation

Multiply 4 and \frac{1}{4} to get 1.

$$x^{2}=4x_{4}+1-3$$

Subtract 3 from 1 to get -2.

$$x^{2}=4x_{4}-2$$

Swap sides so that all variable terms are on the left hand side.

$$4x_{4}-2=x^{2}$$

Add 2 to both sides.

$$4x_{4}=x^{2}+2$$

Divide both sides by 4.

$$\frac{4x_{4}}{4}=\frac{x^{2}+2}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x_{4}=\frac{x^{2}+2}{4}$$

Divide x^{2}+2 by 4.

$$x_{4}=\frac{x^{2}}{4}+\frac{1}{2}$$

Solve for x (complex solution)

$$x=-\sqrt{4x_{4}-2}$$

$$x=\sqrt{4x_{4}-2}$$

Solve for x

$$x=\sqrt{4x_{4}-2}$$

$$x=-\sqrt{4x_{4}-2}\text{, }x_{4}\geq \frac{1}{2}$$