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x=2\sqrt{65} x=-2\sqrt{65}
Take the square root of both sides of the equation.
x^{2}-260=0
Subtract 260 from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-260\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -260 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-260\right)}}{2}
Square 0.
x=\frac{0±\sqrt{1040}}{2}
Multiply -4 times -260.
x=\frac{0±4\sqrt{65}}{2}
Take the square root of 1040.
x=2\sqrt{65}
Now solve the equation x=\frac{0±4\sqrt{65}}{2} when ± is plus.
x=-2\sqrt{65}
Now solve the equation x=\frac{0±4\sqrt{65}}{2} when ± is minus.
x=2\sqrt{65} x=-2\sqrt{65}
The equation is now solved.