Solve x^2=(8-x)^2+4

$$x ^ { 2 } = ( 8 - x ) ^ { 2 } + 4$$

Solve for x

$$x = \frac{17}{4} = 4\frac{1}{4} = 4.25$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(8-x\right)^{2}.

$$x^{2}=64-16x+x^{2}+4$$

Add 64 and 4 to get 68.

$$x^{2}=68-16x+x^{2}$$

Add 16x to both sides.

$$x^{2}+16x=68+x^{2}$$

Subtract x^{2} from both sides.

$$x^{2}+16x-x^{2}=68$$

Combine x^{2} and -x^{2} to get 0.

$$16x=68$$

Divide both sides by 16.

$$x=\frac{68}{16}$$

Reduce the fraction \frac{68}{16} to lowest terms by extracting and canceling out 4.

$$x=\frac{17}{4}$$