Solve for x
x=-1
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x^{2}=4+4x+x^{2}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2+x\right)^{2}.
x^{2}-4x=4+x^{2}
Subtract 4x from both sides.
x^{2}-4x-x^{2}=4
Subtract x^{2} from both sides.
-4x=4
Combine x^{2} and -x^{2} to get 0.
x=\frac{4}{-4}
Divide both sides by -4.
x=-1
Divide 4 by -4 to get -1.
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