Solve x^2=28/3

$$x ^ { 2 } = \frac { 28 } { 3 }$$

Solve for x

$$x = \frac{2 \sqrt{21}}{3} \approx 3.055050463$$

$$x = -\frac{2 \sqrt{21}}{3} \approx -3.055050463$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x=\frac{2\sqrt{21}}{3} x=-\frac{2\sqrt{21}}{3}$$

Steps Using the Quadratic Formula

Subtract \frac{28}{3} from both sides.

$$x^{2}-\frac{28}{3}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{28}{3} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{28}{3}\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{28}{3}\right)}}{2}$$

Multiply -4 times -\frac{28}{3}.

$$x=\frac{0±\sqrt{\frac{112}{3}}}{2}$$

Take the square root of \frac{112}{3}.

$$x=\frac{0±\frac{4\sqrt{21}}{3}}{2}$$

Now solve the equation x=\frac{0±\frac{4\sqrt{21}}{3}}{2} when ± is plus.

$$x=\frac{2\sqrt{21}}{3}$$

Now solve the equation x=\frac{0±\frac{4\sqrt{21}}{3}}{2} when ± is minus.

$$x=-\frac{2\sqrt{21}}{3}$$

The equation is now solved.

$$x=\frac{2\sqrt{21}}{3} x=-\frac{2\sqrt{21}}{3}$$