Solve x^2=14/3

$$x ^ { 2 } = \frac { 14 } { 3 }$$

Solve for x

$$x = \frac{\sqrt{42}}{3} \approx 2.160246899$$

$$x = -\frac{\sqrt{42}}{3} \approx -2.160246899$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$x=\frac{\sqrt{42}}{3} x=-\frac{\sqrt{42}}{3}$$

Steps Using the Quadratic Formula

Subtract \frac{14}{3} from both sides.

$$x^{2}-\frac{14}{3}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{14}{3} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{14}{3}\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{14}{3}\right)}}{2}$$

Multiply -4 times -\frac{14}{3}.

$$x=\frac{0±\sqrt{\frac{56}{3}}}{2}$$

Take the square root of \frac{56}{3}.

$$x=\frac{0±\frac{2\sqrt{42}}{3}}{2}$$

Now solve the equation x=\frac{0±\frac{2\sqrt{42}}{3}}{2} when ± is plus.

$$x=\frac{\sqrt{42}}{3}$$

Now solve the equation x=\frac{0±\frac{2\sqrt{42}}{3}}{2} when ± is minus.

$$x=-\frac{\sqrt{42}}{3}$$

The equation is now solved.

$$x=\frac{\sqrt{42}}{3} x=-\frac{\sqrt{42}}{3}$$