Solve x^2+mx+4=0

$$x ^ { 2 } + m x + 4 = 0$$

Solve for m

$$m=-x-\frac{4}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$mx+4=-x^{2}$$

Subtract 4 from both sides.

$$mx=-x^{2}-4$$

The equation is in standard form.

$$xm=-x^{2}-4$$

Divide both sides by x.

$$\frac{xm}{x}=\frac{-x^{2}-4}{x}$$

Dividing by x undoes the multiplication by x.

$$m=\frac{-x^{2}-4}{x}$$

Divide -x^{2}-4 by x.

$$m=-x-\frac{4}{x}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{m^{2}-16}-m}{2}$$

$$x=\frac{-\sqrt{m^{2}-16}-m}{2}$$

Solve for x

$$x=\frac{\sqrt{m^{2}-16}-m}{2}$$

$$x=\frac{-\sqrt{m^{2}-16}-m}{2}\text{, }|m|\geq 4$$