Solve x^2+bx-15=0

$$x ^ { 2 } + b x - 15 = 0$$

Solve for b

$$b=-x+\frac{15}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$bx-15=-x^{2}$$

Add 15 to both sides.

$$bx=-x^{2}+15$$

The equation is in standard form.

$$xb=15-x^{2}$$

Divide both sides by x.

$$\frac{xb}{x}=\frac{15-x^{2}}{x}$$

Dividing by x undoes the multiplication by x.

$$b=\frac{15-x^{2}}{x}$$

Divide -x^{2}+15 by x.

$$b=-x+\frac{15}{x}$$

Solve for x

$$x=\frac{\sqrt{b^{2}+60}-b}{2}$$

$$x=\frac{-\sqrt{b^{2}+60}-b}{2}$$