Solve x^2+98=3x^2

$$x ^ { 2 } + 98 = 3 x ^ { 2 }$$

Solve for x

$$x=7$$

$$x=-7$$

Steps by Finding Square Root

Subtract 3x^{2} from both sides.

$$x^{2}+98-3x^{2}=0$$

Combine x^{2} and -3x^{2} to get -2x^{2}.

$$-2x^{2}+98=0$$

Subtract 98 from both sides. Anything subtracted from zero gives its negation.

$$-2x^{2}=-98$$

Divide both sides by -2.

$$x^{2}=\frac{-98}{-2}$$

Divide -98 by -2 to get 49.

$$x^{2}=49$$

Take the square root of both sides of the equation.

$$x=7 x=-7$$

Steps Using the Quadratic Formula

Subtract 3x^{2} from both sides.

$$x^{2}+98-3x^{2}=0$$

Combine x^{2} and -3x^{2} to get -2x^{2}.

$$-2x^{2}+98=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -2 for a, 0 for b, and 98 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-2\right)\times 98}}{2\left(-2\right)}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-2\right)\times 98}}{2\left(-2\right)}$$

Multiply -4 times -2.

$$x=\frac{0±\sqrt{8\times 98}}{2\left(-2\right)}$$

Multiply 8 times 98.

$$x=\frac{0±\sqrt{784}}{2\left(-2\right)}$$

Take the square root of 784.

$$x=\frac{0±28}{2\left(-2\right)}$$

Multiply 2 times -2.

$$x=\frac{0±28}{-4}$$

Now solve the equation x=\frac{0±28}{-4} when ± is plus. Divide 28 by -4.

$$x=-7$$

Now solve the equation x=\frac{0±28}{-4} when ± is minus. Divide -28 by -4.

$$x=7$$

The equation is now solved.

$$x=-7 x=7$$