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x^{2}=22-7
Subtract 7 from both sides.
x^{2}=15
Subtract 7 from 22 to get 15.
x=\sqrt{15} x=-\sqrt{15}
Take the square root of both sides of the equation.
x^{2}+7-22=0
Subtract 22 from both sides.
x^{2}-15=0
Subtract 22 from 7 to get -15.
x=\frac{0±\sqrt{0^{2}-4\left(-15\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -15 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-15\right)}}{2}
Square 0.
x=\frac{0±\sqrt{60}}{2}
Multiply -4 times -15.
x=\frac{0±2\sqrt{15}}{2}
Take the square root of 60.
x=\sqrt{15}
Now solve the equation x=\frac{0±2\sqrt{15}}{2} when ± is plus.
x=-\sqrt{15}
Now solve the equation x=\frac{0±2\sqrt{15}}{2} when ± is minus.
x=\sqrt{15} x=-\sqrt{15}
The equation is now solved.